#LyX 1.3 created this file. For more info see http://www.lyx.org/ \lyxformat 221 \textclass article \begin_preamble \usepackage{ragged2e} \RaggedRight \setlength{\parindent}{1 em} \end_preamble \language english \inputencoding auto \fontscheme palatino \graphics default \paperfontsize 12 \spacing single \papersize Default \paperpackage a4 \use_geometry 1 \use_amsmath 0 \use_natbib 0 \use_numerical_citations 0 \paperorientation portrait \leftmargin 1in \topmargin 1in \rightmargin 1.1in \bottommargin 1in \secnumdepth 3 \tocdepth 3 \paragraph_separation indent \defskip medskip \quotes_language english \quotes_times 2 \papercolumns 1 \papersides 1 \paperpagestyle default \layout Title Linear operators \layout Author Paul E. Johnson \layout Section Linear Operator \layout Standard \begin_inset Quotes eld \end_inset Linear operator \begin_inset Quotes erd \end_inset sounds jargonish. But it is a pretty important term. In just about any problem in statistics, the linearity of an operator will make for massive simplification. \layout Subsection Definition \layout Standard A linear operator is one that can \begin_inset Quotes eld \end_inset take in \begin_inset Quotes erd \end_inset a sum and give back a result in the form of a sum of the applied operators. That is, it is like \begin_inset Formula $F()$ \end_inset in an expression like this \begin_inset Formula \[ F(x+y+z)=F(x)+F(y)+F(z)\] \end_inset \newline Here you see that a linear operator has a distributive quality. \layout Standard In my usual poetic style, \layout Quote The operator over a sum is the sum of the applications of the operator. \layout Standard If you throw in constants \begin_inset Formula $a$ \end_inset , \begin_inset Formula $b$ \end_inset , and \begin_inset Formula $c$ \end_inset , then linearity also means that \begin_inset Formula \[ F(ax+by+cz)=aF(x)+bF(y)+cF(z)\] \end_inset \layout Subsection Linear Operators you already know and love. \layout Standard You already know many linear operators. \layout Subsubsection Summation. \layout Standard This is obvious, isn't it? This is just the principle of addition. \begin_inset Formula \[ \sum(x+y)=\sum(x)+\sum(y).\] \end_inset Given two variables, \begin_inset Formula $x=\{ x_{1},x_{2},x_{3},...,x_{N}\}$ \end_inset and \begin_inset Formula $y=\{ y_{1},y_{2},y_{3},...,y_{N}\}$ \end_inset \begin_inset Formula \[ \sum_{i=1}^{N}(x_{i}+y_{i})=\sum_{i=1}^{N}x_{i}+\sum_{i=1}^{N}y_{i}\] \end_inset \layout Subsubsection Expected Value. \layout Standard The Expected Value operator is linear. Recall, for a discrete variable with \begin_inset Formula $m$ \end_inset possible different values, \begin_inset Formula $\{ x_{1},x_{2},...,x_{m}\}$ \end_inset , the expected value is defined as: \begin_inset Formula \[ E(x)=\sum_{i=1}^{m}f(x_{i})\cdot x{}_{i}\] \end_inset \newline What's \begin_inset Formula $E(x+y)$ \end_inset ? Doesn't it depend on the probability distributions for \begin_inset Formula $x$ \end_inset and \begin_inset Formula $y$ \end_inset ? NO. \begin_inset Formula $E(x)$ \end_inset is a linear operator, so \begin_inset Formula \[ E(x+y)=E(x)+E(y)\] \end_inset Since \begin_inset Formula $E()$ \end_inset is a linear operator, it radically simplifies many calculations in statistics. \layout Subsection Operators that you love which are not linear \layout Standard Don't make the mistake of thinking everything that is good is also linear. Recall, for example: \begin_inset Formula \[ V(x+y)=V(x)+V(y)+2Cov(x,y)\] \end_inset Even so, we often try to \begin_inset Quotes eld \end_inset cheat \begin_inset Quotes erd \end_inset and make \begin_inset Formula $V()$ \end_inset act as if it were linear. How many times do you assume away the covariance term? Almost all the time in intermediate regression. \layout Standard I mention this to remind you that, if you want to apply the property of linearity, \shape smallcaps you can only do so when you have some evidence that the operator really is linear. \layout Section The Derivative is a linear operator \layout Standard You might be asked to find the derivative of a sum of functions, such as \begin_inset Formula \begin{eqnarray*} \frac{\partial}{\partial x}\left(f_{1}(x)+f_{2}(x)\right) & = & ?\end{eqnarray*} \end_inset The derivative is a linear operator, apply the \begin_inset Quotes eld \end_inset derivative operator \begin_inset Quotes erd \end_inset \begin_inset Formula $\frac{\partial}{\partial x}$ \end_inset to the individual terms, to find: \begin_inset Formula \[ \frac{\partial f_{1}(x)}{\partial x}+\frac{\partial f_{2}(x)}{\partial x}\] \end_inset \layout Standard The beauty of this is that you can solve a series of small problems and add up the solutions, rather than solving one giant confusing problem. If \begin_inset Formula \[ \frac{\partial f(x)}{\partial x}=7x\] \end_inset and \begin_inset Formula \[ \frac{\partial g(x)}{\partial x}=3x^{2}\] \end_inset then \begin_inset Formula \[ \frac{\partial}{\partial x}\left(f(x)+g(x)\right)=7x+3x^{2}\] \end_inset \layout Section The Integral is also a linear operator. \layout Standard One of the really handy rules is that the integral of a sum is the sum of the integrals. \begin_inset Formula \[ \int\{ f(x)+g(x)\} dx=\int f(x)dx+\int g(x)dx\] \end_inset \the_end